No, it’s not. As desrt says, it doesn’t exist. Draw the graph; it shoots off in different directions depending on whether you approach 8 from the left or from the right. To have a defined limit, you’d need to take the absolute value, i.e. lim(x->8) 1/|x-8|
Of course, you can get round this by declaring x to belong to the one-point compactification of the real line, but I think that’s what was meant…
September 18th, 2006 at 12:59 pm
ROFLASTD! (rolling on the floor laughing and scaring the dog, for the n00bs
)
September 18th, 2006 at 12:59 pm
lim (x->8) 1/(x-8) is not infinity. it does not exist.
September 18th, 2006 at 5:50 pm
desrt: yes it is. The limit of 1/(x-8) as x approaches 8 is infinity.
September 18th, 2006 at 6:13 pm
No, it’s not. As desrt says, it doesn’t exist. Draw the graph; it shoots off in different directions depending on whether you approach 8 from the left or from the right. To have a defined limit, you’d need to take the absolute value, i.e. lim(x->8) 1/|x-8|
Of course, you can get round this by declaring x to belong to the one-point compactification of the real line, but I think that’s what was meant…
September 18th, 2006 at 6:37 pm
definitely not.
a limit as (x->h) f(x) is only defined if 3 conditions hold:
lim (x->h ) f(x) is defined
lim (x->h-) f(x) is defined
lim (x->h ) f(x) == lim (x->h-) f(x)
in this case:
lim(x->8 ) 1/(x-8) = inf
lim (x->8-) 1/(x-8) = -inf
think about:
1/(7.9999999-8) = 1/(small negative number) = -inf
1/(8.0000001-8) = 1/(small positive number) = inf
so lim(x->8) 1/(x-8) does not exist.
September 18th, 2006 at 6:39 pm
oh no! your blog ate all of my plus symbols.
if you see lim (x->h[space]) i actually said (x->h[plus])
September 19th, 2006 at 2:52 am
Here are some more mathematical jewels - the last one, in my opinion, is the best:
http://klab.lv/community/lol/733267.html
September 19th, 2006 at 2:54 am
oh hell, sorry, didn’t check the link on top
September 20th, 2006 at 9:06 pm
Thanks for the refresher on limits. It’s been too long…